вычислите: (2-1и3/4*2/7)(1и1/3-2и1/2:3и3/4):2и1/3:(1/4-5/6+7/8. Created by sabina002017. algebra-ru

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sabina002017 @sabina002017

July 2022 1 7 Report

вычислите:

(2-1и3/4*2/7)(1и1/3-2и1/2:3и3/4):2и1/3:(1/4-5/6+7/8

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Regent1828

Verified answer

Скорее всего, в условии пропущены скобки в конце:
(2 - 1 3/4 * 2/7)(1 1/3 - 2 1/2 : 3 3/4) : (2 1/3 : (1/4 - 5/6 + 7/8)) =
= (2 - 1/2)(1 1/3 - 5/2 * 4/15) : (7/3 : (6/24 - 20/24 + 21/24)) =
= 1,5 * (4/3 - 2/3) : (7/3 : 7/24) = 3/2 * 2/3 : (7/3 * 24/7) = 1 : 8 = 1/8 = 0,125

По действиям:
1). 1 3/4 * 2/7 = 7/4 * 2/7 = 2/4 = 1/2
2). 2 - 1/2 = 3/2
3). 2 1/2 : 3 3/4 = 5/2 * 4/15 = 2/3
4). 1 1/3 - 2/3 = 4/3 - 2/3 = 2/3
5). 3/2 * 2/3 = 1
6). 1/4 - 5/6 + 7/8 = 6/24 - 20/24 + 21/24 = 7/24
7). 2 1/3 : 7/24 = 7/3 * 24/7 = 8
8). 1 : 8 = 1/8 = 0,125

Если условие правильное, тогда:
1 : 2 1/3 : (1/4 - 5/6 + 7/8) = 1 : 7/3 : 7/24 = 3/7 * 24/7 = 72/49

2 votes Thanks 1

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