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losano765
@losano765
July 2022
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8sin2x - 16cosx = 0
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harutyunyan46
Вспомним sin2x= 2sinx.cosx формуле и получим 16 sinx. cosx-16cosx =0. 16cosx (sinx-1) =0 . cosx =0 или sinx=1 .cosx=0 x=90+180k . sinx=1 x=90+360k . Так как второй решение принадлежит в первом решение .то получим x=90+ 180 *k .
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