[tex]\displaystyle \left \{ {{8x+2y=-6} \atop {-y-x^2=6}} \right.\\ \\\left \{ {{8x+2y=-6} \atop {y=-6-x^2}} \right. \\\\8x+2(-6-x^2)=-6\\x=1,x=3\\y=-6-1^2;y=-6-3^2\\y=-7,y=-15\\(x_1,y_1)=(1,-7),(x_2,y_2)=(3,-15)[/tex]
Ответ:
решение на фотографии
Copyright © 2024 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
Verified answer
[tex]\displaystyle \left \{ {{8x+2y=-6} \atop {-y-x^2=6}} \right.\\ \\\left \{ {{8x+2y=-6} \atop {y=-6-x^2}} \right. \\\\8x+2(-6-x^2)=-6\\x=1,x=3\\y=-6-1^2;y=-6-3^2\\y=-7,y=-15\\(x_1,y_1)=(1,-7),(x_2,y_2)=(3,-15)[/tex]
Ответ:
решение на фотографии