[tex]\displaystyle\bf\\\frac{(x+2)(x-3)}{5} \geq 0\\\\\\\frac{(x+2)(x-3)}{5} \cdot 5\geq 0\cdot 5\\\\\\(x+2)(x-3)\geq 0\\\\\\+ + + + + [-2] - - - - - [3] + + + + + \\\\\\Otvet \ : \ x\in\Big(-\infty \ ; \ -2\Big] \ \cup \ \Big[3 \ ; \ +\infty\Big)[/tex]