Ответ:
[tex] - \frac{2}{3} [/tex]
Объяснение:
[tex] \frac{a {x}^{2} - {a}^{3} }{3 {x}^{3} - 3 {a}^{2}x } = \frac{a( {x}^{2} - {a}^{2} )}{3x( {x}^{2} - {a}^{2}) } = \frac{a}{3x} [/tex]
підставляємо
[tex] \frac{a}{3x} = \frac{ \frac{8}{9} }{3 \times ( - \frac{4}{9} )} = \frac{ \frac{8}{9} }{ - \frac{4}{3} } = \frac{8}{9} \times ( - \frac{3}{4} ) = - \frac{2}{3} [/tex]
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Answers & Comments
Ответ:
[tex] - \frac{2}{3} [/tex]
Объяснение:
[tex] \frac{a {x}^{2} - {a}^{3} }{3 {x}^{3} - 3 {a}^{2}x } = \frac{a( {x}^{2} - {a}^{2} )}{3x( {x}^{2} - {a}^{2}) } = \frac{a}{3x} [/tex]
підставляємо
[tex] \frac{a}{3x} = \frac{ \frac{8}{9} }{3 \times ( - \frac{4}{9} )} = \frac{ \frac{8}{9} }{ - \frac{4}{3} } = \frac{8}{9} \times ( - \frac{3}{4} ) = - \frac{2}{3} [/tex]