[tex]f(x) = \frac{x + 5}{x - 1} \\ f(0) = \frac{0 + 5}{0 - 1} = \frac{5}{ - 1} = - 5 \\ f(3) = \frac{3 + 5}{3 - 1} = \frac{8}{2} = 4[/tex]