=6(а²+а+1)\18(а³-1)=6(а²+а+1) \ 18(а-1)(а²+а+1)=1\3(а-1)
=(а-3)*(а²+3а+9) \ 8(а-3)=а²+3а+9 \8
=а(х-у)-3(х+у) \(3-а)(3+а)=(а-3)(х-у)\(3-а)(3+а)=у-х \3+а
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=6(а²+а+1)\18(а³-1)=6(а²+а+1) \ 18(а-1)(а²+а+1)=1\3(а-1)
=(а-3)*(а²+3а+9) \ 8(а-3)=а²+3а+9 \8
=а(х-у)-3(х+у) \(3-а)(3+а)=(а-3)(х-у)\(3-а)(3+а)=у-х \3+а