решите неравенство 5(7-x)-6x<=0
найдите значение выражения b/a-b x (1/a-1/b) при а=1/9, b=корень из 2
5(7-х)-6x<=0
35-5x-6x<=0
11x=>35
x=>35/11
b/a-b*(1/a-1/b)=b/a-b/a+b/b=1
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5(7-х)-6x<=0
35-5x-6x<=0
11x=>35
x=>35/11
b/a-b*(1/a-1/b)=b/a-b/a+b/b=1