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Helpmeplece
@Helpmeplece
March 2022
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9 класс,синусы косинусы алгебра
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sedinalana
Verified answer
4
a)1-2sin²a=cos²a+sin²a-2sin²a=cos²a-sin²a
cos²a-sin²a=cos²a-sin²a
b)(sina+cosa)/(sin²a-cos≡a)(sin²a+cos²a)=(sina+cosa)/(sina-cosa)(sina+cosa)=1/(sina-cosa)
1/(sina-cosa)=1/(sina-cosa)
5
a)cos(a-b)/sinasinb-1=(cosacosb=sinasina-sinasina)/siasinb=
=cosacosb/sinasinb=ctgactgb
b)(1+cos2a+sin2a)/(cosa+sina)=
=(cos²a+sin²a+cos²a-sin²a+2sinacosa)/(cosa+sina)=
(2cos²a+2sinacosa)/(cosa+sina)=2cosa(cosa+sina)/(cosa+sina)=2cosa
6
sinx+cosx=1/3
(sinx+cosx)²=1/9
sin²x+2sinxcosx+cos²x=1/9
1+2sinxcosx=1/9
2sinxcosx=-8/9
sinxcosx=-4/9
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Answers & Comments
Verified answer
4a)1-2sin²a=cos²a+sin²a-2sin²a=cos²a-sin²a
cos²a-sin²a=cos²a-sin²a
b)(sina+cosa)/(sin²a-cos≡a)(sin²a+cos²a)=(sina+cosa)/(sina-cosa)(sina+cosa)=1/(sina-cosa)
1/(sina-cosa)=1/(sina-cosa)
5
a)cos(a-b)/sinasinb-1=(cosacosb=sinasina-sinasina)/siasinb=
=cosacosb/sinasinb=ctgactgb
b)(1+cos2a+sin2a)/(cosa+sina)=
=(cos²a+sin²a+cos²a-sin²a+2sinacosa)/(cosa+sina)=
(2cos²a+2sinacosa)/(cosa+sina)=2cosa(cosa+sina)/(cosa+sina)=2cosa
6
sinx+cosx=1/3
(sinx+cosx)²=1/9
sin²x+2sinxcosx+cos²x=1/9
1+2sinxcosx=1/9
2sinxcosx=-8/9
sinxcosx=-4/9