W(елем)=n(Ar(елем)*100/Mr(в-ва)
Ar(B)=11
Mr(B2О3)=22+48=70
W(B) =2*11*100/70=31,43%
W(O)=100-31,43= 68,57%
Ответ: 31,43% ; 68,57%.
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W(елем)=n(Ar(елем)*100/Mr(в-ва)
Ar(B)=11
Mr(B2О3)=22+48=70
W(B) =2*11*100/70=31,43%
W(O)=100-31,43= 68,57%
Ответ: 31,43% ; 68,57%.