Ответ:
Пошаговое объяснение:
1) f(x)'= -sin(2x-π); f(0)'= -sin(2*0-π)=0; f(π)'= -sin(2*π-π)=0;
2) f(x)'=x'+tg2x'=1+2/cos²(2x); f(0)'=1+2/cos²(2*0)=1+2=3; f(π)'=1+2/cos²(2*π)=1+2=3;
3) f(x)'=(3sin(x/3-π/2))'=cos(x/3-π/2); f(0)'=cos(0/3-π/2)=0;
f(π)'=cos(π/3-π/2)=0,866.
4) f(x)'= -sin(x/2); f(0)'=-sin(0/2)=0; f(π)'=-sin(π/2)=-1
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Ответ:
Пошаговое объяснение:
1) f(x)'= -sin(2x-π); f(0)'= -sin(2*0-π)=0; f(π)'= -sin(2*π-π)=0;
2) f(x)'=x'+tg2x'=1+2/cos²(2x); f(0)'=1+2/cos²(2*0)=1+2=3; f(π)'=1+2/cos²(2*π)=1+2=3;
3) f(x)'=(3sin(x/3-π/2))'=cos(x/3-π/2); f(0)'=cos(0/3-π/2)=0;
f(π)'=cos(π/3-π/2)=0,866.
4) f(x)'= -sin(x/2); f(0)'=-sin(0/2)=0; f(π)'=-sin(π/2)=-1