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Ответ:

Объяснение:

1. [tex]\frac{9a^2}{b}+\frac{4a^2}{b}=\frac{9a^2+4a^2}{b} = \frac{13a^2}{b}[/tex]

Ответ: Г

2. 1) [tex]\frac{a+b}{8} -\frac{a-5b}{8} =\frac{a+b-a+5b}{8} =\frac{6b}{8}=\frac{3b}{4}[/tex]

2) [tex]\frac{b+2}{4b}+\frac{5-3c}{12c} =\frac{3bc+6c+5b-3bc}{12bc}= \frac{5b+6c}{12bc}[/tex]

3) [tex]\frac{10}{m^2+5m} -\frac{2}{m} =\frac{10-2(m+5)}{m(m+5)}=\frac{10-2m-10}{m(m+5)}=\frac{-2m}{m(m+5)}=-\frac{2}{m+5}[/tex]

3.[tex]\frac{x^2+25y^2}{x-5y} +\frac{10xy}{5y-x} = \frac{x^2+(5y)^2}{x-5y} -\frac{10xy}{x-5y}=\frac{x^2+(5y)^2-10xy}{x-5y} =\frac{(x-5y)^2}{x-5y} =x-5y[/tex]

Подставляем наши значения x и y: 2017 - 5 * 1/5 = 2017 - 1 = [tex]\fbox{2016}[/tex]