Verified answer

#include <iostream>

#include <cmath>

using namespace std;

int main()

{

   double a, b, x, y;

   cout << "Enter a: ";

   cin >> a;

   cout << "Enter b: ";

   cin >> b;

   x = log(abs(a/sin(a))) * exp(pow(b, 2) - 3*b + 1);

   y = 3 * sqrt(tan(5*pow(a, 3) - 3*pow(b, 2)));

   cout << "x = " << x << endl;

   cout << "y = " << y << endl;

   return 0;

}

Решение во вложении

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