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Ответ:

1)[tex]\frac{15a^{2} - 10ab}{3ab-2b^{2} }=\frac{5a(3a-2b)}{b(3a-2b)} =\frac{5a}{b}\\[/tex];  [tex]\frac{5*(-3)}{-0,2} =75[/tex]

2)[tex]\frac{9c^{2}-4d^{2} }{18c^{2}d-12cd^{2} } =\frac{(3c-2d)(3c+2d)}{6cd(3c-2d)} =\frac{(3c+2d)}{6cd}[/tex];  [tex]\frac{(3c+2d)}{6cd}=1,2[/tex]

3)[tex]\frac{6x^{2}+12xy }{5xy+10y^{2} } =\frac{6x(x+2y)}{5y(x+y)} =\frac{6x}{5y}[/tex]; [tex]\frac{6x}{5y}=-2[/tex]

4)[tex]\frac{x^{2} +6xy+9y^{2} }{4x^{2} +12xy} =\frac{(x+3y)^{2} }{4x(x+3y)} =\frac{x+3y}{4x}[/tex]; [tex]\frac{x+3y}{4x} =2,5[/tex]