Cr2O3
Mr(Cr2O3) = 2 × 52 + 3 × 16 = 152
w(Cr) = 2 × 52 / 152 × 100% = 68%
w(O) = 3 × 16 / 152 × 100% = 32%
Al(OH)3
Mr(Al(OH)3) = 1 × 27 + 3 × 16 + 3 × 1 = 78
w(Al) = 1 × 27 / 78 × 100% = 35%
w(O) = 3 × 16 / 78 × 100% = 61%
w(H) = 3 × 1 / 78 × 100% = 4%
Copyright © 2025 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
Cr2O3
Mr(Cr2O3) = 2 × 52 + 3 × 16 = 152
w(Cr) = 2 × 52 / 152 × 100% = 68%
w(O) = 3 × 16 / 152 × 100% = 32%
Al(OH)3
Mr(Al(OH)3) = 1 × 27 + 3 × 16 + 3 × 1 = 78
w(Al) = 1 × 27 / 78 × 100% = 35%
w(O) = 3 × 16 / 78 × 100% = 61%
w(H) = 3 × 1 / 78 × 100% = 4%