Мне нужно решение 2:1/4+((1целая1/2+2целая2/3):3целая3/4-2/3):8целая8/9=. Created by 87765724237g. matematika-ru

1+2=+=+==44/3=/=*=*==11-=-=-2/=/=*=8/=*=*=8+=8

9=...

June 2022 1 23 Report

Мне нужно решение 2:1/4+((1целая1/2+2целая2/3):3целая3/4-2/3):8целая8/9=

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ПанфиловаКристина 1 $\frac{1}{2}$ +2 $\frac{2}{3}$ = $\frac{3}{2}$ + $\frac{8}{3}$ = $\frac{9}{6}$ + $\frac{16}{6}$ = $\frac{25}{6}$ =4 $\frac{1}{6}$
4 $\frac{1}{6}$ /3 $\frac{3}{4}$ = $\frac{25}{6}$ / $\frac{15}{4}$ = $\frac{25}{6}$ * $\frac{4}{15}$ = $\frac{5}{3}$ * $\frac{2}{3}$ = $\frac{10}{9}$ =1 $\frac{1}{9}$
1 $\frac{1}{9}$ - $\frac{2}{3}$ = $\frac{10}{9}$ - $\frac{2}{3}$ = $\frac{10}{9}$ - $\frac{6}{9}$ $\frac{4}{9}$
2/ $\frac{1}{4}$ = $\frac{2}{1}$ / $\frac{1}{4}$ = $\frac{2}{1}$ * $\frac{4}{1}$ =8
$\frac{4}{9}$ / $\frac{80}{9}$ = $\frac{4}{9}$ * $\frac{9}{80}$ = $\frac{1}{1}$ * $\frac{1}{20}$ = $\frac{1}{20}$
8+ $\frac{1}{20}$ =8 $\frac{1}{2}$

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