99. Решите уравнение:
1) 3 (x-1) – 2(x+2) = 4х + 8;
2) 4(х+1,5) + 3 (1 - x) = 10;
3) 4 (3х + 2) — 7(х+1) = 3 (x-1);
4) 2,5 (2x + 3) – 2(x+2, 5) = 3, 5+ 2х.
1) 3 (x-1) – 2(x+2) = 4х + 8;
2) 4(х+1,5) + 3 (1 - x) = 10;
3) 4 (3х + 2) — 7(х+1) = 3 (x-1);
4) 2,5 (2x + 3) – 2(x+2, 5) = 3, 5+ 2х.
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Ответ:
1)3(x-1)-2(x+2)=4x+8
3x-3-2x+4=4x+8
3x-2x-4x=3-4+8
-3x=7
x=7/3
2)4(x+1,5)+3(1-x)=10
4x+6+3-3x=10
4x-3x=-6-3+10
x=1
3)4(3x+2)-7(x+1)=3(x-1)
12x+8-7x+7=3x-3
12x-7x-3x=-8-7-3
2x=-18
x=-9
4)2,5(2x+3)-2(x+2,5)=3,5+2x
5x+7,5-2x+5=3,5+2x
5x-2x-2x=-7,5-5+3,5
x=-9