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Demalena
@Demalena
July 2022
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Найдите сумму 1/(1⋅2)+1/(2⋅3)+⋯+1/(99⋅100)
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ViktorC
1/(1*2)+1/(2*3)+...+1/(99*100)=(2-1)/(1*2)+(3-2)/(2*3)+...+(100-99)/(99*100)=
1/1-1/2+1/2-1/3+...+1/99-1/100=99/100
9 votes
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