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Maksim22876
@Maksim22876
August 2022
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Решите неравенство:
1) 2^x < 1/2
2) (1/3)^x > 1/27
3) (2/3)^(3x+6) > 4/9
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сашаok
1)2^х <1/2
2^х+1 <1
х+1 <0
х <-1
2) 1/3^х>1\27
1/3^х-3>1
х-3 <0
х <3
3)2/3^3х+6>4/9
2/3^3х+6-2>1
3х+4>0
3х>-4
х>-4/3
2 votes
Thanks 1
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Answers & Comments
2^х+1 <1
х+1 <0
х <-1
2) 1/3^х>1\27
1/3^х-3>1
х-3 <0
х <3
3)2/3^3х+6>4/9
2/3^3х+6-2>1
3х+4>0
3х>-4
х>-4/3