Ответ: (3a-b-4)(3a-b+4)
[tex]\displaystyle\bf\\9a^{2} -6ab+b^{2}-16= \Big(9a^{2} -6ab+b^{2}\Big)-16= \\\\\\=\Big[\Big(3a\Big)^{2} -2\cdot 3a\cdot b+b^{2} \Big]-16=\Big(3a-b\Big)^{2} -4^{2} =\\\\\\=\Big(3a-b-4\Big)\Big(3a-b+4\Big)[/tex]
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Ответ: (3a-b-4)(3a-b+4)
[tex]\displaystyle\bf\\9a^{2} -6ab+b^{2}-16= \Big(9a^{2} -6ab+b^{2}\Big)-16= \\\\\\=\Big[\Big(3a\Big)^{2} -2\cdot 3a\cdot b+b^{2} \Big]-16=\Big(3a-b\Big)^{2} -4^{2} =\\\\\\=\Big(3a-b-4\Big)\Big(3a-b+4\Big)[/tex]