Home
О нас
Products
Services
Регистрация
Войти
Поиск
Tori163
@Tori163
September 2021
2
14
Report
Разложите на множители:
а)100а^4-1/9b^2
b)9x²-(x-1)²
в)x³+y^6
Please enter comments
Please enter your name.
Please enter the correct email address.
Agree to
terms of service
You must agree before submitting.
Send
Answers & Comments
hraky
A) (10a^2-1/(3b))(
10a^2+1/(3b))
б) (3x-x+1)(3x+x-1)=(2x+1)(4x-1)
в) (x+y^2)(x^2-xy^2+y^4)
1 votes
Thanks 3
litanalove
A) 10²a^4-1/3²b^4=
=(10a²-1/3b²)(10a²+1/3b²)
b) пусть (x-1)=a, тогда
9х²-a²=(3x-a)(3x+a)=
=(3x-x+1)(3x+x-1)=
=(2x-1)(4x+1)
в) x^3+y^6=(x+y²)(х²-xy²+y^4)
2 votes
Thanks 2
×
Report "9b^2 b)9x²-(x-1)² в)x³+y^6..."
Your name
Email
Reason
-Select Reason-
Pornographic
Defamatory
Illegal/Unlawful
Spam
Other Terms Of Service Violation
File a copyright complaint
Description
Helpful Links
О нас
Политика конфиденциальности
Правила и условия
Copyright
Контакты
Helpful Social
Get monthly updates
Submit
Copyright © 2025 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
б) (3x-x+1)(3x+x-1)=(2x+1)(4x-1)
в) (x+y^2)(x^2-xy^2+y^4)
=(10a²-1/3b²)(10a²+1/3b²)
b) пусть (x-1)=a, тогда
9х²-a²=(3x-a)(3x+a)=
=(3x-x+1)(3x+x-1)=
=(2x-1)(4x+1)
в) x^3+y^6=(x+y²)(х²-xy²+y^4)