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valeriya7345
@valeriya7345
July 2022
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Запишите в виде бесконечной десятичной периодической дроби 11/9;22/9
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Divaltor
11/9 = 1,(2) - 2 в периоде
22/9 = 2,(4) - 4 в периоде
4 votes
Thanks 3
Fizikomat
1,222222222...или 2,2(2)
2,4444444.... или 2,4(4)
2 votes
Thanks 1
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Answers & Comments
22/9 = 2,(4) - 4 в периоде
2,4444444.... или 2,4(4)