Ответ:

см фото

Объяснение:

Verified answer

[tex]\displaystyle\bf\\y=\frac{6x+1}{5} \\\\y\in\Big[-3 \ ; \ 1\Big]\\\\\\-3\leq \frac{6x+1}{5} \leq 1\\\\\\-3\cdot 5\leq \frac{6x+1}{5} \cdot 5\leq 1\cdot 5\\\\\\-15\leq 6x+1\leq 5\\\\\\-15-1\leq 6x+1-1\leq 5-1\\\\\\-16\leq 6x\leq 4\\\\\\-16:6\leq 6x:6\leq 4:6\\\\\\-2\frac{2}{3} \leq x\leq \frac{2}{3} \\\\\\Otvet \ : \ x\in\Big[-2\frac{2}{3} \ ; \ \frac{2}{3} \Big][/tex]