(a-3)в квадрате - (a-2)(a+4) (b+7)в квадрате - (b+3)(b+6) (b+3)в квадрате - 6b(b+1). Created by dasha9102000. algebra-ru

(a-3)в квадрате - (a-2)(a+4) (b+7)в квадрате - (b+3)(b+6) (b+3)в квадрате

dasha9102000 @dasha9102000

July 2022 1 4 Report

(a-3)в квадрате - (a-2)(a+4)
(b+7)в квадрате - (b+3)(b+6)
(b+3)в квадрате - 6b(b+1)

Answers & Comments

eugeke

Verified answer

$(a-3)^2-(a-2)(a+4)=a^2-6a+9-(a^2+2a-8)=\\\\
=a^2-6a+9-a^2-2a+8=17-8a$

$(b+7)^2-(b+3)(b+6)=b^2+14b+49-(b^2+9b+18)=\\\\
=b^2+14b+49-b^2-9b-18=5b+31$

$(b+3)^2-6b(b+1)=b^2+6b+9-6b^2-6b=9-5b^2$

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dasha9102000 August 2022 | 0 Ответы

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dasha9102000 August 2022 | 0 Ответы

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Answers & Comments

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