Ответ:
[tex](4 + \sqrt{a} )(4 - \sqrt{a} ) = 16 - a[/tex]
[tex]( \sqrt{b} + \sqrt{c} )( \sqrt{b} - \sqrt{c} ) = b - c[/tex]
[tex]( \sqrt{m} + \sqrt{5} ) {}^{2} - (m + 5) = m + 2 \sqrt{5m} + 5 - m - 5 = 2 \sqrt{5m} [/tex]
[tex](n + 10) - ( \sqrt {10} - \sqrt{n} ) {}^{2} = (n + 10) -( 10 - 2 \sqrt{10n} + n) = n + 10 - 10 + 2 \sqrt{10n} - n = 2 \sqrt{10n} [/tex]
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Ответ:
[tex](4 + \sqrt{a} )(4 - \sqrt{a} ) = 16 - a[/tex]
[tex]( \sqrt{b} + \sqrt{c} )( \sqrt{b} - \sqrt{c} ) = b - c[/tex]
[tex]( \sqrt{m} + \sqrt{5} ) {}^{2} - (m + 5) = m + 2 \sqrt{5m} + 5 - m - 5 = 2 \sqrt{5m} [/tex]
[tex](n + 10) - ( \sqrt {10} - \sqrt{n} ) {}^{2} = (n + 10) -( 10 - 2 \sqrt{10n} + n) = n + 10 - 10 + 2 \sqrt{10n} - n = 2 \sqrt{10n} [/tex]