Ответ:
(a-5)² -3(a-3)(a+3)-(2a-1)(3-a)=a²−10a+25−3(a−3)−(2a−1)(3−a)=a²−10a+25−3a+9−(2a−1)(3−a)=a²−13a+34−(2a−1)(3−a)=a²−13a+34−(7a−2a²-3)=a²−13a+34−7a+2a²+3=3a²−20a+34+3=
3a²−20a+37
Объяснение:
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Ответ:
(a-5)² -3(a-3)(a+3)-(2a-1)(3-a)=a²−10a+25−3(a−3)−(2a−1)(3−a)=a²−10a+25−3a+9−(2a−1)(3−a)=a²−13a+34−(2a−1)(3−a)=a²−13a+34−(7a−2a²-3)=a²−13a+34−7a+2a²+3=3a²−20a+34+3=
3a²−20a+37
Объяснение: