a) 5р^2 - 5q^2 = 5(p^2 - q^2) = 5(p - q)(p + q)
б) 24 - 6a^2 = 6(4 - a^2) = 6(2 - a)(2 + a)
в) 3у^4 - 3у^2 = 3y^2(y^2 - 1) = 3y^2(y - 1)(y + 1)
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Answers & Comments
a) 5р^2 - 5q^2 = 5(p^2 - q^2) = 5(p - q)(p + q)
б) 24 - 6a^2 = 6(4 - a^2) = 6(2 - a)(2 + a)
в) 3у^4 - 3у^2 = 3y^2(y^2 - 1) = 3y^2(y - 1)(y + 1)