a) 9a = ...... = 12a
b) ...... –5m = –2m
c) ...... –3b = 0
N2.
2x – x + 4x – 3x
N3
a) –(x – 5y)
b) x + (2y – 7) – z
N4
c) 4a ・ 16
d) 20c : 5
N5
a) 3 (4k – 5)
b) (b – 3) (–2)
c) 2 (4a + 5) – 4a
N6
(a + b) – (a – b) = (c + b) – (c – b)
N7
4a 3 2a = 6a + 3
4a 3 2a = 2a + 3
4a 3 2a = 24a
4a 3 2a = –2a
Copyright © 2024 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
a) 9a +3a = 12a
b) 3m – 5m = –2m
c) 3b – 3b = 0
N2.
2x – x + 4x – 3x = 1x + 1x = 2x
N3
a) –(x – 5y) = -x + 5y
b) x + (2y – 7) – z = x + 2y - 7 - z
N4
c) 4a ・ 16 = 64a
d) 20c : 5 = 4c
N5
a) 3 (4k – 5) = 12k - 15
b) (b – 3) (–2) = -2b + 6
c) 2 (4a + 5) – 4a = 8a + 10 - 4a = 4a + 10
N6
(a + b) – (a – b) = (c + b) – (c – b)
a + b - a + b = c + b - c + b
2b = 2b
N7
4a + 3 + 2a = 6a + 3
4a + 3 - 2a = 2a + 3
4a ・ 3 ・2a = 24a
4a - (3 ・ 2a) = –2a