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utinaanya
@utinaanya
August 2022
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А как решить бикваратное уравнение?
X*4-18x*2+48=0?
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nKrynka
X*4-18x*2+48=0
x^2 = y
y^2 - 18y + 48 = 0
D = 324 - 4*1*48 = 132
y1 = (18 - 2
√33)/2
y2 = (18 + 2√33)/2
x^2 = 9 - √33
x1 = √(9 -√33)
x2 = √(9 + √33)
2 votes
Thanks 1
utinaanya
Большое спасибо)
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Answers & Comments
x^2 = y
y^2 - 18y + 48 = 0
D = 324 - 4*1*48 = 132
y1 = (18 - 2√33)/2
y2 = (18 + 2√33)/2
x^2 = 9 - √33
x1 = √(9 -√33)
x2 = √(9 + √33)