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linazelenskaya
@linazelenskaya
July 2021
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Помогите сделать Алгебру, даю 40 баллов.
№1
Выполните действия
a) x/y - x/x-5
б) а+3/а+2 - а+2/а+1
в) 3у/ув квадрате+4у+4 + 3/у+2
г) b/b-c - b в квадрате/b в квадрате -c в квадрате
№2
Упростите выражение:
1/а+b - 1/b-a - 2b/a в квадрате-b
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Answers & Comments
армения20171
A)x/y-x/(x-5)=(x(x-5)-xy)/y(x-5)=
(x²-5x-xy)/y(x-5)
b)(a+3)/(a+2)-(a+2)/(a+1)=
((a+3)(a+1)-(a+2)²)/(a+1)(a+2)
=(a²+a+3a+3-a²-4a-4)/(a+1)(a+2)=
-4/(a+1)(a+2)
2)1/(a+b)-1/(b-a)-2b/a√b=
(b-a-a-b)/(b²-a²)-2*b*√b/(a*(√b)²=
-2a/(b²-a²)-2√b/a=
(-2a²-2√b(b²-a²))/a(b²-a²)
2 votes
Thanks 3
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Answers & Comments
(x²-5x-xy)/y(x-5)
b)(a+3)/(a+2)-(a+2)/(a+1)=
((a+3)(a+1)-(a+2)²)/(a+1)(a+2)
=(a²+a+3a+3-a²-4a-4)/(a+1)(a+2)=
-4/(a+1)(a+2)
2)1/(a+b)-1/(b-a)-2b/a√b=
(b-a-a-b)/(b²-a²)-2*b*√b/(a*(√b)²=
-2a/(b²-a²)-2√b/a=
(-2a²-2√b(b²-a²))/a(b²-a²)