A) x^2-(3-x)^2 > 0B) (x+5)^2-(x-2)(x+7) < 0C) (x-3)(x-9)-(3-x)^2 (знак не строгого неравенства 0Помогите решить квадратные неравенства . Created by polina1403. matematika-ru

A) x^2-(3-x)^2 > 0B) (x+5)^2-(x-2)(x+7) < 0C) (x-3)(x-9)-(3-x)^2 (знак не ...

May 2022 1 34 Report

A) x^2-(3-x)^2 > 0
B) (x+5)^2-(x-2)(x+7) < 0
C) (x-3)(x-9)-(3-x)^2 (знак не строгого неравенства <) 0
D)(2x-5)^2-6(2x-5)>0

Помогите решить квадратные неравенства

Answers & Comments

UroborusUrius Ответ:A) x^2-(3-x)^2 > 0x²-(9-6x+x²)>0x²-9+6x-x²>0-9+6x>06x>9x>3/2B) (x+5)^2-(x-2)(x+7) < 0x²+10x+25-(x²+7x-2x-14)<0x²+10x+25-(x²+5x-14)<0x²+10x+25-x²-5x+14<05x+39<05x< -39x< -39/5C) (x-3)(x-9)-(3-x)^2≤0x²-9x-3x+27-(9-6x+x²)≤0x²-9x-3x+27-9+6x-x²≤0-6x+18≤0-6x≤ -18x≥3D)(2x-5)^2-6(2x-5)>04x²-20x+25-12x+30>04x²-32x+55>04x²-10x-22x+55>02x*(2x-5)-11(2x-5)>0(2x-5)*(2x-11)>02x-5>02x-11>02x-5<02x-11<0Ответ: x принадлежит (-∞,5/2)U(11/2,+∞)

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