Ответ:
[tex](\frac{1}{x^3})' = (x^{-3})' = -3*x^{-4} = -\frac{3}{x^{4} }[/tex]
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Ответ:
[tex](\frac{1}{x^3})' = (x^{-3})' = -3*x^{-4} = -\frac{3}{x^{4} }[/tex]