Verified answer

Ответ:

a)   1.3

b)   [tex]\displaystyle 9\frac{5}{6}[/tex]

Объяснение:

a)

[tex]\displaystyle \frac{1}{14} *\sqrt{49} +\sqrt{0.64} =\frac{1}{14} *\sqrt{7*7} +\sqrt{0.8*0.8} =\frac{1}{14} *7+0.8=\frac{1}{2} +0.8=\\\\\\=0.5+0.8=1.3[/tex]

b)

[tex]\displaystyle \sqrt{11^2-21} -\sqrt{\frac{7}{9} -\frac{3}{4} }=\sqrt{121-21} -\sqrt{\frac{7*4-9*3}{9*4} } =\\\\\\=\sqrt{100} -\sqrt {\frac{28-27}{9*4} }=10-\frac{1}{3*2} =10-\frac{1}{6} =9\frac{5}{6}[/tex]