a1= 10, n = 11, Sn = 330. Найти an, d
Sn=(a1+an)n/2
отсюда находим an
2Sn=(a1+an)n
a1= 10, n = 11,Sn = 330
330*2=11(10+an)
660=11(10+an)
10+an=60
an=50
an=a1+d(n-1)
a1= 10, n = 11
50=10+d(11-1)
40=d10
d=4
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Sn=(a1+an)n/2
отсюда находим an
2Sn=(a1+an)n
a1= 10, n = 11,Sn = 330
330*2=11(10+an)
660=11(10+an)
10+an=60
an=50
an=a1+d(n-1)
a1= 10, n = 11
50=10+d(11-1)
40=d10
d=4