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kdenisenko920
@kdenisenko920
August 2021
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А)10-3у=-4+7у
б)3(4-с)=6-(8с+3)
г)1,6b-0,4=3,2-0,8(2-b)
д)2(n-3)-4(5-2n)=-5(4n+7)
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Report "А)10-3у=-4+7уб)3(4-с)=6-(8с+3)г)1,6b-0,4=3,2-0,8(2-b)д)2(n-3)-4(5-2n)=-5(4n+7)..."
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