Ответ:
5)
[tex] \frac{ - kp {}^{3} }{p {}^{4} t} = \frac{ - k}{pt} [/tex]
6)
[tex] \frac{5xyz}{15y {}^{2} z} = \frac{x}{3y} [/tex]
7)
[tex] \frac{22x {}^{2}y }{ - 33y {}^{2} x} = \frac{2x}{3y} [/tex]
8)
[tex] \frac{t {}^{7} p {}^{8} }{p {}^{6} t {}^{9} } = \frac{p {}^{2} }{t {}^{2} } [/tex]
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Answers & Comments
7)= 2x/-3y 8)= p2/t2 ( 2 це в квадраті)
Ответ:
5)
[tex] \frac{ - kp {}^{3} }{p {}^{4} t} = \frac{ - k}{pt} [/tex]
6)
[tex] \frac{5xyz}{15y {}^{2} z} = \frac{x}{3y} [/tex]
7)
[tex] \frac{22x {}^{2}y }{ - 33y {}^{2} x} = \frac{2x}{3y} [/tex]
8)
[tex] \frac{t {}^{7} p {}^{8} }{p {}^{6} t {}^{9} } = \frac{p {}^{2} }{t {}^{2} } [/tex]