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galinaleonova1
@galinaleonova1
August 2022
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помогите решить ( (8+а^3)/(16-a) )*( (a^2+4)/a^2-2a+4) )
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litanalove
=((2 +a)(4 -2a +a^2)*(a^2 +4)) /(4 -a^2)(4+a^2)*(a^2 -2a +4) =
=((2 +a)(a^2 -2a +a^2)) /(4 -a^2)(a^2 -2a +4) =
=(2 +a) /(4 - a^2) =(2 +a) /(2 -a)(2 +a) =
=1 /(2 -a)
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Answers & Comments
=((2 +a)(a^2 -2a +a^2)) /(4 -a^2)(a^2 -2a +4) =
=(2 +a) /(4 - a^2) =(2 +a) /(2 -a)(2 +a) =
=1 /(2 -a)