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minkaeva
@minkaeva
August 2022
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а^2+5>_10(a-2)
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SonRiDol
А^2+5>_10а-20
а^2-10а+5+20>_0
а^2-10а+5+20=0
a^2-10a+25=0
D=100-4×25×1=100-100=1
10+-1
a1,2=---------
2
a1=11/2=5,5
a2=9/2=4,5
[5,5;+знак бесконечности)
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Answers & Comments
а^2-10а+5+20>_0
а^2-10а+5+20=0
a^2-10a+25=0
D=100-4×25×1=100-100=1
10+-1
a1,2=---------
2
a1=11/2=5,5
a2=9/2=4,5
[5,5;+знак бесконечности)