a^2+ab...

chukanova2015 @chukanova2015

July 2022 1 2 Report

a+b/a^2-4b+4a-b^2*16-b^2-a^2-2ab/a^2+ab

Answers & Comments

zhenyaM2002

Verified answer

$\frac{a+b}{a^2-4b +4a - b^2} * \frac{16-b^2-a^2-2ab}{a^2+ab} = \\ \\ 
= \frac{a+b}{(a-b)(a+b) + 4(a-b)} * \frac{16- (b^2+a^2+2ab) }{a(a+b)}= \\ \\ 
= \frac{a+b}{(a-b)(a+b+4) } * \frac{16- (a+b)^2}{a(a+b) } = \\ \\ 
= \frac{(4-(a+b))(4+a+b)}{a(a-b)(a+b+4)} = \frac{4-(a+b)}{a(a-b)}$

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