a^2+ab)...

July 2022 1 8 Report

(a/a^2-b^2)-(a/a^2+ab)

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nelle987

Verified answer

$\dfrac a{a^2-b^2}-\dfrac a{a^2+ab}=\dfrac a{(a-b)(a+b)}-\dfrac a{a(a+b)}=\dfrac a{(a-b)(a+b)}-\\-\dfrac 1{a+b}=\dfrac{a-(a-b)}{(a-b)(a+b)}=\dfrac b{a^2-b^2}$

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