a^2b-ab^2-ac+ab+bc-c разложить на множетели
c(b-a-1)+ba(a+1)-ab^2
(b-a-1)*(c-ab)
a^2b-ab^2-ac+ab+bc-c=(b-a-1)*(c-ab)
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c(b-a-1)+ba(a+1)-ab^2
(b-a-1)*(c-ab)
a^2b-ab^2-ac+ab+bc-c=(b-a-1)*(c-ab)