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October 2021
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(1-a)/(1-a+a^2) - 2/(1+a) + (-3-7a+2a^2)/(a^3+1)
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sedinalana
Verified answer
1
(1-a)/(1-a+a²)-2/(1+a)+(-3-7a+2a²)/(1+a)(1-a+a²)=
=(1-a²-2+2a-2a²-3-7a+2a²)/(1+a³)=(-a²-5a-4)/(1+a³)=
=-(a²+5a+4)/(1+a³)=-(a+1)(a_4)/(1+a)(1-a+a²)=(a+4)/(-1+a-a²)
2
√(x+3)=7x-5
ОДЗ
x+3≥0⇒x≥-3 U 7x-5≥0⇒7x≥5⇒x≥5/7
x∈[5/7;∞)
возведем в квадрат
x+3=49x²-70x+25
49x²-71x+22=0
D=5041-4312=729
x1=(71-27)/98=44/98=22/49<5/7 не удов усл
х2=(71+27)/98=1
2 votes
Thanks 3
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Answers & Comments
Verified answer
1(1-a)/(1-a+a²)-2/(1+a)+(-3-7a+2a²)/(1+a)(1-a+a²)=
=(1-a²-2+2a-2a²-3-7a+2a²)/(1+a³)=(-a²-5a-4)/(1+a³)=
=-(a²+5a+4)/(1+a³)=-(a+1)(a_4)/(1+a)(1-a+a²)=(a+4)/(-1+a-a²)
2
√(x+3)=7x-5
ОДЗ
x+3≥0⇒x≥-3 U 7x-5≥0⇒7x≥5⇒x≥5/7
x∈[5/7;∞)
возведем в квадрат
x+3=49x²-70x+25
49x²-71x+22=0
D=5041-4312=729
x1=(71-27)/98=44/98=22/49<5/7 не удов усл
х2=(71+27)/98=1