(a+3)^2 a^2-4 ----------- * ---------- 2a-4 3a+9. Created by MrSvitoi. algebra-ru

(a+3)^2 a^2-4 ----------- * ---------- 2a-4 3a+9...

May 2021 1 12 Report

(a+3)^2 a^2-4
----------- * ----------
2a-4 3a+9

Answers & Comments

ГородскаяОхотница $\frac{(a + 3)^2}{2a - 4} * \frac{a^2 - 4}{3a + 9} = \frac{(a + 3)^2}{2 (a - 2)} * \frac{(a - 2)(a + 2)}{3 (a + 3)} = \frac{(a + 3)(a + 2)}{6} = \frac{a^2 + 5a + 6}{6}$

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