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dima12213
@dima12213
July 2022
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a)5x-8=7x+12
б)0,2у+1,6=0,3у-1,6
в)одна вторая x+три восьмых=одна четвертых x= три тридцать вторых (тут дроби)
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nareshka00
А)5х-7х=12+8
-2х=20
х=-10
б)0.2у-0.3у=-1.6-1.6
-0.1у=-3.2
у=32
В)(х/2)-(х/4)=(3/32)-(3/8)
х/4=-1/32
х=-1/8
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dima12213
Спасибо большое!
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Answers & Comments
-2х=20
х=-10
б)0.2у-0.3у=-1.6-1.6
-0.1у=-3.2
у=32
В)(х/2)-(х/4)=(3/32)-(3/8)
х/4=-1/32
х=-1/8