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aliganrus
@aliganrus
July 2022
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Пусть a-1/a=2/3 найдите (a^12+1)/a^6
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mv5666851
(a^12+1)/a^6=((a^12-2a^6+1)+2a^6)/a^6=(a-1)^6/a^6+2a^6/a^6=((a-1)/a)^6+2=(2/3)^6+2=64/729+2=2целых 64/729
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