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tea74
@tea74
August 2021
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а)6x²>5x-1
б)-5x²<6-11x
Решить с помощью метода интервалов
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KarinaYouchi
А) 6x^2>5x-1
6x^2-5x+1>0
6x^2-5x+1=0
D=(-5)^2-4*6*1=25-24=1
x1=5+√1=5+1=6=1\2
2*6 12 12
x2=5-√1=5-1=4=1\3
2*6 12 12
6x^2-5x+1=6(x-1\2)(x-1\3)
6(x-1\2)(x-1/3)>0
+ - +
/////////////// //////////////
-------------(1\3)------------------(1\2)-------------
Ответ:(-∞;1\3)U(1\2;+∞)
б) -5x^2<6-11x
-5x^2-6+11x<0
-5x^2+11x-6<0
-5x^2+11x-6=0
D=11^2-4*(-5)*(-6)=121-120=√1
x1=-11+√1=-11+1=-10\-10=1
2*(-5) -10
x2=-11-√1=-11-1=-12\-10=1.2
2*(-5) -10
-5x+11x-6=-5(x-1)(x-1.2)
-5(x-1)(x-1.2)<0
- + -
////////////////// /////////////////////
-----------------(1)----------------(1.2)----------------------
Ответ: (-∞;1)U(1.2;+∞)
2 votes
Thanks 1
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Answers & Comments
6x^2-5x+1>0
6x^2-5x+1=0
D=(-5)^2-4*6*1=25-24=1
x1=5+√1=5+1=6=1\2
2*6 12 12
x2=5-√1=5-1=4=1\3
2*6 12 12
6x^2-5x+1=6(x-1\2)(x-1\3)
6(x-1\2)(x-1/3)>0
+ - +
/////////////// //////////////
-------------(1\3)------------------(1\2)-------------
Ответ:(-∞;1\3)U(1\2;+∞)
б) -5x^2<6-11x
-5x^2-6+11x<0
-5x^2+11x-6<0
-5x^2+11x-6=0
D=11^2-4*(-5)*(-6)=121-120=√1
x1=-11+√1=-11+1=-10\-10=1
2*(-5) -10
x2=-11-√1=-11-1=-12\-10=1.2
2*(-5) -10
-5x+11x-6=-5(x-1)(x-1.2)
-5(x-1)(x-1.2)<0
- + -
////////////////// /////////////////////
-----------------(1)----------------(1.2)----------------------
Ответ: (-∞;1)U(1.2;+∞)