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kamilagalimova
@kamilagalimova
August 2022
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a×(a+d-c)+c×(a-d-c)+d×(d-a+c)
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Юленька194
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A×(a+d-c)+c×(a-d-c)+d×(d-a+c)=а²+ad -ac +ac-cd-c²+d²-ad+cd=a²+d²-c +ad-ad -ac +ac -cd+cd=a²+d²-c
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A×(a+d-c)+c×(a-d-c)+d×(d-a+c)=а²+ad -ac +ac-cd-c²+d²-ad+cd=a²+d²-c +ad-ad -ac +ac -cd+cd=a²+d²-c