Объяснение:

по теореме синусов:

[tex] \frac{AB}{ \sin∠C} = 2r \\ \frac{AB}{ \sin(135) } = 2 \times \sqrt{2} \\\frac{AB}{ \sin(180-45) } = 2 \times \sqrt{2} \\ \frac{AB}{ \sin(45) } = 2 \times \sqrt{2} \\ \frac{AB}{ \frac{ \sqrt{2} }{2} } = 2 \sqrt{2} \\ \frac{2AB}{ \sqrt{2} } = 2 \sqrt{2} \\ AB = 4[/tex]