Home
О нас
Products
Services
Регистрация
Войти
Поиск
syuzbaghdasaryan05
@syuzbaghdasaryan05
June 2023
1
3
Report
вычислить площадь правильного шестиугольника если AB=6см , AA¹=15см
Please enter comments
Please enter your name.
Please enter the correct email address.
Agree to
terms of service
You must agree before submitting.
Send
Answers & Comments
zmeura1204
Verified answer
Ответ:
Sбок=540см²
Sпол=540+108√3 см²
Решение:
Sосн=6*АВ²√3/4=6*6²√3/4=
=54√3 см²
Росн=6*АВ=6*6=36см.
Sбок=Росн*АА1=36*15=540см²
Sпол=Sбок+2*Sосн=
=540+2*54√3=540+108√3
1 votes
Thanks 2
More Questions From This User
See All
syuzbaghdasaryan05
August 2022 | 0 Ответы
iz sleduyushej serii materialov o2 kcl c3h8 cu ba ch3oh kakie molekulyarnye
Answer
syuzbaghdasaryan05
August 2022 | 0 Ответы
chto veshestvo ne rastvoryaetsya v vode 1 solyanaya kislota 2 mednaya latun 3 benzo
Answer
syuzbaghdasaryan05
July 2022 | 0 Ответы
87 76 pomagite rishit etu zadachu ya pishu ne idealna potomushte ya neznayau
Answer
syuzbaghdasaryan05
July 2022 | 0 Ответы
pomogite pomogitepostavte slova v pravilnom poryadke
Answer
syuzbaghdasaryan05
July 2022 | 0 Ответы
isklyucheno dlya materialov s atomnoj kristallicheskoj reshetkoj pomagite pzh
Answer
×
Report "вычислить площадь правильного шестиугольника если AB=6см , AA¹=15см "
Your name
Email
Reason
-Select Reason-
Pornographic
Defamatory
Illegal/Unlawful
Spam
Other Terms Of Service Violation
File a copyright complaint
Description
Helpful Links
О нас
Политика конфиденциальности
Правила и условия
Copyright
Контакты
Helpful Social
Get monthly updates
Submit
Copyright © 2024 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
Verified answer
Ответ:Sбок=540см²
Sпол=540+108√3 см²
Решение:
Sосн=6*АВ²√3/4=6*6²√3/4=
=54√3 см²
Росн=6*АВ=6*6=36см.
Sбок=Росн*АА1=36*15=540см²
Sпол=Sбок+2*Sосн=
=540+2*54√3=540+108√3