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shabalindenis99
@shabalindenis99
October 2021
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(a+b+c)^2-(a-b-c)^2 разложить на множители
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krugly1981
Verified answer
( a + b+ c)² - ( a - b - c)² = (a+b+c-a+b+c)(a+b+c+a-b-c) = (2b+2c)×2a=
= 2a(2b + 2c) = 4a(b+c)
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Answers & Comments
Verified answer
( a + b+ c)² - ( a - b - c)² = (a+b+c-a+b+c)(a+b+c+a-b-c) = (2b+2c)×2a== 2a(2b + 2c) = 4a(b+c)